A) \[9\times {{10}^{-3}}J\]
B) \[9\times {{10}^{-3}}eV\]
C) \[2eV/m\]
D) Zero
Correct Answer: A
Solution :
By using \[U=9\times {{10}^{9}}\frac{{{Q}_{1}}{{Q}_{2}}}{r}\] Þ \[U=9\times {{10}^{9}}\times \frac{{{10}^{-6}}\times {{10}^{-6}}}{1}=9\times {{10}^{-3}}J\]You need to login to perform this action.
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