A) \[8\times {{10}^{-11}}\]C
B) \[2\times {{10}^{-12}}\]C
C) \[3\times {{10}^{-11}}\]C
D) \[6\times {{10}^{-10}}\]C
Correct Answer: A
Solution :
\[E=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Q}{{{r}^{2}}}\]Þ \[2=9\times {{10}^{9}}\times \frac{Q}{{{(0.6)}^{2}}}\]Þ Q = 8 ´ \[{{10}^{-11}}C\]You need to login to perform this action.
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