A) 2.5 micro-coulomb
B) 2.0 micro-coulomb
C) 1.0 micro-coulomb
D) 0.5 micro-coulomb
Correct Answer: D
Solution :
\[E=9\times {{10}^{9}}\times \frac{Q}{{{r}^{2}}}\,\Rightarrow 500=9\times {{10}^{9}}\times \frac{Q}{{{(3)}^{2}}}\]Þ Q = 0.5 mCYou need to login to perform this action.
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