A) ? 2.03 V
B) 1.36 V
C) 2.7 V
D) 2.03 V
Correct Answer: C
Solution :
\[E_{\text{cell}}^{o}=E_{\text{cathode}}^{o}-{{E}_{\text{anode}}}\]; \[E_{\text{cell}}^{o}=0.34-(-\,2.37)\] \[E_{\text{cell}}^{o}=2.71\,\,V\].You need to login to perform this action.
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