A) + 3.04 volts
B) ? 3.04 volts
C) + 2.36 volts
D) ? 2.36 volts
Correct Answer: D
Solution :
Mg lies above Cu in electrochemical series and hence Cu electrode acts as cathode \[E_{cell}^{o}=E_{C{{u}^{++}}/Cu}^{o}-E_{M{{g}^{++}}/Mg}^{o}\] \[2.70\,\,V=0.34-E_{M{{g}^{++}}/Mg}^{o}\]; \[E_{M{{g}^{++}}/Mg}^{o}=-2.36\,\,V\].You need to login to perform this action.
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