A) \[{{K}_{0}}\]
B) Zero
C) \[\frac{{{K}_{0}}}{2}\]
D) Not obtainable
Correct Answer: A
Solution :
Since maximum value of \[{{\cos }^{2}}\omega t\]is 1. \[\therefore {{K}_{\max }}={{K}_{o}}{{\cos }^{2}}\omega t={{K}_{o}}\] Also \[{{K}_{\max }}=P{{E}_{\max }}={{K}_{o}}\]You need to login to perform this action.
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