A) \[U=-\frac{K{{X}^{2}}}{2}\]
B) \[U=K{{X}^{2}}\]
C) \[U=K\]
D) \[U=KX\]
Correct Answer: A
Solution :
\[F=-\,kx\] Þ \[dW=Fdx=-\,kxdx\] So \[\int_{\,0}^{\,W}{dW}=\int_{\,0}^{\,x}{-kx\,dx}\]Þ \[W=U=-\frac{1}{2}k{{x}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec