A) \[{{x}^{2}}+{{y}^{2}}-2ax-2ay+{{a}^{2}}=0\]
B) \[{{x}^{2}}+{{y}^{2}}+ax+ay-{{a}^{2}}=0\]
C) \[{{x}^{2}}+{{y}^{2}}+2ax+2ay-{{a}^{2}}=0\]
D) \[{{x}^{2}}+{{y}^{2}}-ax-ay+{{a}^{2}}=0\]
Correct Answer: A
Solution :
Required equation is \[{{(x-a)}^{2}}+{{(y-a)}^{2}}={{a}^{2}}\] \[\Rightarrow {{x}^{2}}+{{y}^{2}}-2ax-2ay+{{a}^{2}}=0\].
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