A) - \[6/5\]
B) 4/3
C) - 4/3
D) None of these
Correct Answer: B
Solution :
\[\frac{{{e}^{5x}}+{{e}^{x}}}{{{e}^{3x}}}={{e}^{2x}}+{{e}^{-2x}}=2\left\{ 1+\frac{{{(2x)}^{2}}}{2\ !}+\frac{{{(2x)}^{4}}}{4\ !}+...... \right\}\] Coefficient of\[{{x}^{4}}=2.\frac{{{2}^{4}}}{4\ !}=\frac{4}{3}\].You need to login to perform this action.
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