A) 1
B) \[-1\]
C) 1/2
D) -1/2
Correct Answer: C
Solution :
\[(1+x+{{x}^{2}}){{e}^{-x}}=(1+x+{{x}^{2}})\] \[\left\{ 1-\frac{x}{1\ !}+\frac{{{x}^{2}}}{2\ !}-\frac{{{x}^{3}}}{3\ !}+....... \right\}\] Coefficient of \[{{x}^{2}}=1.\frac{1}{2\ !}+1.\left( -\frac{1}{1\ !} \right)+1.1=\frac{1}{2\ !}=\frac{1}{2}\].You need to login to perform this action.
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