A) 10 V
B) 30 V
C) 45 V
D) 90 V
Correct Answer: A
Solution :
\[|e|\,=\frac{d\varphi }{dt}=\frac{d}{dt}(5{{t}^{2}}+3t+16)=(10t+3)\] when \[t=3\sec ,\ {{e}_{3}}=(10\times 3+3)=33\ V\] when \[t=4\sec ,\ {{e}_{4}}=(10\times 4+3)=43\ V\] Hence emf induced in fourth second \[={{e}_{4}}-{{e}_{3}}=43-33=10\ V\]You need to login to perform this action.
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