A) 0.012 V
B) 0.05 V
C) 0.1 V
D) 0.2 V
Correct Answer: D
Solution :
\[e=\frac{-NBA(\cos {{\theta }_{2}}-\cos {{\theta }_{1}})}{\Delta t}\] \[=-\frac{500\times 4\times {{10}^{-4}}\times 0.1(\cos 90-\cos 0)}{0.1}=0.2\ V\]You need to login to perform this action.
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