A) \[\text{250}\sqrt{\text{3}}\,\,\text{N to right}\]
B) \[\text{250 N to right}\]
C) \[\text{250}\sqrt{3}\text{ N to left}\]
D) \[\text{250 N to left}\]
Correct Answer: C
Solution :
Here, m = 100 g = 0.1 kg \[v=5m{{s}^{-1}},t=2\times {{10}^{-3}}s\] \[\theta =60{}^\circ \] As \[F\times t=\]Change in momentum \[=2mv\sin \theta \] Or \[F=\frac{2mv\sin \theta }{t}=\frac{2\times 0.1\times 5\times \sin 60{}^\circ }{2\times {{10}^{-3}}}\] \[=500\times \sin 60{}^\circ =250\sqrt{3}N\] to leftYou need to login to perform this action.
You will be redirected in
3 sec