A) 6000 N
B) 60000 N
C) 60 N
D) 600 N.
Correct Answer: B
Solution :
Here, rate of burning fuel, \[\frac{dm}{dt}=1kg{{s}^{-1}}\] Velocity of fuel ejection, \[v=60km\,\,{{s}^{-1}}=60000m{{s}^{-1}}\] Thrust \[=\frac{dm}{dt}\cdot v=1\times 60000=60000N\] Thus, force exerted on rocket is 60000N.You need to login to perform this action.
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