A) \[1.32\times {{10}^{-4}}amp-{{m}^{2}}\]
B) \[2.62\times {{10}^{-4}}amp\text{-}{{m}^{2}}\]
C) \[5.25\times {{10}^{-4}}amp\text{-}{{m}^{2}}\]
D) \[7.85\times {{10}^{-4}}amp\text{-}{{m}^{2}}\]
Correct Answer: D
Solution :
\[M=iA=0.1\times \pi \times {{\left( 0.05 \right)}^{2}}\] \[=\left( 0.1 \right)\times 3.14\times 25\times {{10}^{-4}}=7.85\times {{10}^{-4}}amp-{{m}^{2}}\]
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