JEE Main & Advanced Mathematics Definite Integration Question Bank Fundamental definite integration, Definite integration by substitution

  • question_answer
    \[\int_{0}^{2\pi }{\sqrt{1+\sin \frac{x}{2}}\,dx=}\]            [MNR 1987; UPSEAT 2000]

    A)                 0             

    B)                 2

    C)                 8             

    D)                 4

    Correct Answer: C

    Solution :

               \[\int_{0}^{2\pi }{\sqrt{1+\sin \frac{x}{2}}dx}=\int_{0}^{2\pi }{\left| \sin \frac{x}{4}+\cos \frac{x}{4} \right|dx=4\left[ \sin \frac{x}{4}-\cos \frac{x}{4} \right]}_{0}^{2\pi }\]                                                        \[=4[1-0-0+1]=8\].


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