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JEE Main & Advanced Mathematics Definite Integration Question Bank Fundamental definite integration, Definite integration by substitution

  • question_answer
    \[\int_{0}^{2\pi }{\,\,(\sin x+\cos x)\,dx=}\]                                        [SCRA 1991]

    A)                 0             

    B)                 2

    C)                 \[-2\]    

    D)                 1

    Correct Answer: A

    Solution :

                    \[\int_{0}^{2\pi }{(\sin x+\cos x)dx=[-\cos x+\sin x]_{0}^{2\pi }=0}\].


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