A) Unit vector
B) Null vector
C) Vector of magnitude \[\sqrt{2}\]
D) Scalar
Correct Answer: A
Solution :
\[\vec{P}=\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j}\]\\[|\vec{P}|=\sqrt{{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}+{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}}\]= 1 \ It is a unit vector.You need to login to perform this action.
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