A) 4320
B) 216
C) - 216
D) - 4320
Correct Answer: D
Solution :
\[{{T}_{r+1}}=\,{}^{6}{{C}_{r}}{{(2x)}^{6-r}}{{\left( -\frac{3}{x} \right)}^{r}}\] = \[{}^{6}{{C}_{r}}{{(2)}^{6-r}}{{(-3)}^{r}}{{(x)}^{6-2r}}\] For term independent of x, 6 - 2r = 0 i.e. r = 3 \ \[{{T}_{4}}={{\,}^{6}}{{C}_{3}}\,{{2}^{6-3}}{{(-3)}^{3}}\] = - 4320.You need to login to perform this action.
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