A) 10th
B) 9th
C) 8th
D) 7th
Correct Answer: B
Solution :
\[{{T}_{r+1}}={}^{12}{{C}_{r}}{{(2{{x}^{2}})}^{12-r}}{{(-1)}^{r}}{{\left( \frac{1}{x} \right)}^{r}}\] For term independent of x, \[24-3r=0\Rightarrow r=8\]. So, 9th term independent of x.You need to login to perform this action.
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