A) \[{{98}^{o}}\]
B) \[{{108}^{o}}\]
C) \[\angle P={{95}^{o}}\]
D) \[\angle C={{40}^{o}}\]
Correct Answer: D
Solution :
In PABC, \[{{60}^{o}}+{{x}^{o}}+{{45}^{o}}={{180}^{o}}\] \[{{90}^{o}}\]\[\square ABCD\] \[\Rightarrow \] \[\angle 1=\angle 2=\angle 3=\angle 4={{90}^{o}}\] \[AB=CD\] In \[\square ABDE\],\[{{360}^{o}}\] Let \[{{270}^{o}}\]You need to login to perform this action.
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