A) \[\angle A={{60}^{o}},\]
B) \[CE||BA\]
C) \[\angle ECD={{65}^{o}}\]
D) \[\angle ACB=\]
Correct Answer: B
Solution :
\[\angle DCA={{180}^{o}}\] and AC is a transversal. \[\angle EAB={{124}^{o}}\]\[\angle ABC\] (Alternate angles) \[\angle C={{40}^{o}}\] \[{{65}^{o}}\] Now \[{{105}^{o}}\] (\[{{95}^{o}}\]\[{{85}^{o}}\] form a linear pair) \[\angle A={{60}^{o}},\]You need to login to perform this action.
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