A) \[25{}^\circ \]
B) \[50{}^\circ \]
C) \[40{}^\circ \]
D) \[130{}^\circ \]
Correct Answer: A
Solution :
Angle subtended by Arc ABC at the centre \[\therefore \]Angle subtended by Arc ABC at any point on the circumference \[={{25}^{o}}\] \[\therefore \] \[\angle ABC={{180}^{o}}-{{25}^{o}}={{155}^{o}}\] [Since opposite angles of a cyclic quadrilateral are supplementary] \[\therefore \] \[\angle CBD={{180}^{o}}-{{155}^{o}}={{25}^{o}}\]You need to login to perform this action.
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