A) \[80{}^\circ \]
B) \[100{}^\circ \]
C) \[120{}^\circ \]
D) \[140{}^\circ \]
Correct Answer: C
Solution :
From \[\Delta \,CAB,\] \[\angle C={{180}^{o}}-({{80}^{o}}+{{40}^{o}})={{60}^{o}}\] \[\therefore \] \[\angle D={{60}^{o}}\] Thus, from \[\Delta \,DAB,\] \[\angle DAB+ABD={{180}^{o}}-\angle D\] \[={{180}^{o}}-{{60}^{o}}={{120}^{o}}\]You need to login to perform this action.
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