Answer:
On the surface of any planet, \[g=\frac{4}{3}\pi GR\rho \] \[\therefore \] \[\frac{{{g}_{1}}}{{{g}_{2}}}=\frac{\frac{4}{3}\pi G{{R}_{1}}{{\rho }_{1}}}{\frac{4}{3}\pi G{{R}_{2}}{{\rho }_{2}}}={{R}_{1}}{{\rho }_{1}}:{{R}_{2}}{{\rho }_{2}}.\]
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