Answer:
For inverse square law, \[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\] \[\therefore \] Acceleration of body \[A=\frac{F}{{{m}_{1}}}=\frac{G{{m}_{2}}}{{{r}^{2}}}=a\] For inverse fourth power law, \[F'=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{4}}}\] Acceleration of body \[A=\frac{F'}{{{m}_{1}}}=\frac{G{{m}_{2}}}{{{r}^{4}}}=\frac{a}{{{r}^{2}}}\].
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