A) \[\frac{1}{9}m\]
B) \[\frac{1}{10}m\]
C) \[\frac{1}{11}m\]
D) \[\frac{10}{11}m\]
Correct Answer: C
Solution :
Let at distance r from the smaller body, intensity of gravitational field becomes zero, then \[\frac{G\times 10000}{{{(1-r)}^{2}}}=\frac{G\times 100}{{{r}^{2}}}\] \[100\,\,{{r}^{2}}={{(1-r)}^{2}}\] \[\Rightarrow \] \[10r={{(1-r)}^{2}}\] \[\Rightarrow \] \[11r=1\] \[\Rightarrow \] \[r=\frac{\mathbf{1}}{\mathbf{11}}\mathbf{m}\].You need to login to perform this action.
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