A) \[0.\text{414R}\]
B) R
C) 2R
D) 3.5R
Correct Answer: A
Solution :
\[g'=\frac{g{{R}^{2}}}{{{r}^{2}}}=\frac{g}{2}\] \[\Rightarrow \] \[{{r}^{2}}=2{{R}^{2}}\] \[\Rightarrow \] \[r=R\sqrt{2}=R+h\] \[\Rightarrow \] \[h=R(\sqrt{2}-1)\] \[=R(1.414-1)\] \[=\mathbf{0}\mathbf{.414}\,\,\mathbf{R}\].You need to login to perform this action.
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