A) 21 mF
B) 23 mF
C) \[\frac{3}{14}\mu F\]
D) \[\frac{14}{3}\mu F\]
Correct Answer: D
Solution :
Given circuit is balanced Whetstone bridge. So capacitor of 2mF can be dropped from the circuit Þ \[{{C}_{AB}}=2+\frac{8}{3}=\frac{14}{3}\mu F\]You need to login to perform this action.
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