A) 2 V
B) 4 V
C) 1 V
D) 6 V
Correct Answer: D
Solution :
Equivalent capacitance \[\frac{1}{{{C}_{eq}}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}\] Þ \[{{C}_{eq}}=\frac{6}{11}\mu F\] Charge supplied from battery \[Q=\frac{6}{11}\times 11=6\mu C\] Hence potential difference across 1mF capacitor \[=\frac{6}{1}=6V\]You need to login to perform this action.
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