A) \[2.5\mu F\]
B) \[15\,\mu F\]
C) \[1.5\mu F\]
D) \[0.1\mu F\]
Correct Answer: D
Solution :
The capacitance across A and B \[=\frac{{{C}_{1}}}{2}+{{C}_{1}}+{{C}_{1}}=\frac{5}{2}{{C}_{1}}\] As Q = CV, \[1.5\mu C=\frac{5}{2}{{C}_{1}}\times 6\] Þ \[{{C}_{1}}=\frac{1.5}{15}\times {{10}^{-6}}\] \[=0.1\times {{10}^{-6}}F=0.1\mu F.\]You need to login to perform this action.
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