A) 1 : 15
B) 15 : 1
C) 1 : 1
D) 1 : 3
Correct Answer: A
Solution :
\[\frac{1}{{{C}_{s}}}=\frac{1}{3}+\frac{1}{9}+\frac{1}{18}=\frac{1}{2}\] Þ \[{{C}_{s}}=2\mu F\] \[{{C}_{p}}=3+9+18=30\mu F\] Þ \[\frac{{{C}_{s}}}{{{C}_{p}}}=\frac{2}{30}=\frac{1}{15}\]You need to login to perform this action.
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