A) \[2400\ ergs\]
B) \[1800\ ergs\]
C) \[3600\ ergs\]
D) \[5400\ ergs\]
Correct Answer: B
Solution :
Total capacitance of given system \[{{C}_{eq}}=\frac{8}{5}\mu F\] \[U=\frac{1}{2}{{C}_{eq}}{{V}^{2}}=\frac{1}{2}\times \frac{8}{5}\times {{10}^{-6}}\times 225=180\times {{10}^{-6}}J\] \[=180\times {{10}^{-6}}\times {{10}^{7}}erg=1800\,erg\]You need to login to perform this action.
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