A) ? 142.5 kJ
B) + 142.5 kJ
C) ? 285 kJ
D) + 285 kJ
Correct Answer: C
Solution :
For the decomposition of 9gm of water heat required \[=142.5\,kJ\] we know \[{{H}_{2}}O=2+16=18\] Therefore heat required for decomposition of 18gm water \[=\frac{18}{9}\times 142.5=285\,KJ\] Than, enthalpy of formation of water is reverse of heat required = ? 285 kJ.You need to login to perform this action.
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