A) 0
B) 3/2
C) ? 3/2
D) ½
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{6(g)}}+\frac{15}{2}{{O}_{2(g)}}\to 6C{{O}_{2(g)}}+3{{H}_{2}}{{O}_{(g)}}\] \[\Delta n=6+3-1-\frac{15}{2}=+\frac{1}{2}\].You need to login to perform this action.
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