A) \[B{{F}_{3}}\] and \[NC{{l}_{3}}\]
B) \[{{H}_{2}}S\]and \[BeC{{l}_{2}}\]
C) \[B{{F}_{3}},NC{{l}_{3}}\]and \[{{H}_{2}}S\]
D) \[S{{F}_{4}}\]and \[BeC{{l}_{2}}\]
E) \[NC{{l}_{3}}\] and \[{{H}_{2}}S\]
Correct Answer: E
Solution :
In \[NC{{l}_{3}}\] and \[{{H}_{2}}S\] the central atom of both (N and S) are in \[s{{p}^{3}}\]hybridization state while in \[B{{F}_{3}}\] and \[NC{{l}_{3}}\] central atoms are in \[s{{p}^{2}}\] and \[s{{p}^{3}}\]hybridization respectively. In \[{{H}_{2}}S\] and \[BeC{{l}_{2}}\] central atom are in \[s{{p}^{3}}\]and \[s{{p}^{2}}\] hybridization In \[B{{F}_{3}},\,NC{{l}_{3}}\] & \[{{H}_{2}}S\] central atom are in \[s{{p}^{2}}\], \[s{{p}^{3}}\] & \[s{{p}^{3}}\] hybridization and in the central atom are in \[s{{p}^{3}}\]and \[sp\]hybridization.You need to login to perform this action.
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