A) \[s{{p}^{3}}\] hybridisation
B) \[s{{p}^{2}}\] hybridisation
C) \[sp\] hybridisation
D) \[{{d}^{2}}s{{p}^{3}}\] hybridization
Correct Answer: C
Solution :
\[{{C}_{\text{ground state}}}=2{{s}^{2}},2{{p}_{x}}^{1}{{p}_{y}}^{1}\]; \[{{C}_{\text{excited state }}}=2{{s}^{1}},2{{p}_{x}}^{1}{{p}_{y}}^{1}{{p}_{z}}^{1}\] \[{{O}_{\text{ground state }}}=2{{s}^{2}},2{{p}_{x}}^{2}{{p}_{y}}^{1}{{p}_{z}}^{1}\] In the formation of \[C{{O}_{2}}\] molecule, hybridization of orbitals of carbon occur only to a limited extent involving only one s and one p orbitals there is thus sp hybridisation of valence shell orbitals of the carbon atom resulting in the formation of two sp hybrid orbitals.You need to login to perform this action.
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