A) 3.4
B) 2.6
C) 1.5
D) 1.8
Correct Answer: D
Solution :
\[pH=-\text{log}\,\,{{K}_{b}}+\text{log}\frac{\text{ }\!\![\!\!\text{ Salt }\!\!]\!\!\text{ }}{\text{ }\!\![\!\!\text{ Acid }\!\!]\!\!\text{ }}\] \[pH=-\text{log}\,[1.8\times {{10}^{-5}}]+\text{log}\frac{\text{ }\!\![\!\!\text{ Salt }\!\!]\!\!\text{ }}{\text{1}\text{.0}}\] \[9=4.7+\log \frac{\text{ }\!\![\!\!\text{ Salt }\!\!]\!\!\text{ }}{1.0}\] ; \[\log \frac{\text{ }\!\![\!\!\text{ Salt }\!\!]\!\!\text{ }}{1.0}=4.7-9=-4.3\] \[\frac{\text{ }\!\![\!\!\text{ Salt }\!\!]\!\!\text{ }}{1.0}=\text{Antilog}\frac{1}{4.3};\,\,[S\text{alt }\!\!]\!\!\text{ }=1.8\]You need to login to perform this action.
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