A) \[1:10\]
B) \[10:1\]
C) \[5:4\]
D) \[4:5\]
Correct Answer: B
Solution :
\[pH=-\log {{K}_{b}}+\log \frac{[\text{salt}]}{\text{ }\!\![\!\!\text{ acid }\!\!]\!\!\text{ }}\] \[5=-\log {{10}^{-4}}+\log \frac{[\text{salt}]}{\text{ }\!\![\!\!\text{ acid }\!\!]\!\!\text{ }}\] \[\log \frac{[\text{salt}]}{\text{ }\!\![\!\!\text{ acid }\!\!]\!\!\text{ }}=1\] \[\frac{[\text{salt}]}{\text{ }\!\![\!\!\text{ acid }\!\!]\!\!\text{ }}=\text{antilog}\,1=10:1\]You need to login to perform this action.
You will be redirected in
3 sec