A) \[1\times {{10}^{-2}}mole/litre\]
B) \[1\times {{10}^{-11}}mole/litre\]
C) \[1\times {{10}^{-14}}mole/litre\]
D) \[1\times {{10}^{-12}}mole/litre\]
Correct Answer: B
Solution :
0.001 M \[NaOH\]means \[[O{{H}^{-}}]={{10}^{-3}}\]; \[pOH=3\] \[pH+pOH=14;\,\,pH=14-3\] \[pH=11\]; \[[{{H}^{+}}]={{10}^{-11}}\]mole-litre?1You need to login to perform this action.
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