A) 1
B) 2
C) 3
D) 11
Correct Answer: C
Solution :
\[[{{H}^{+}}]=C\,.\,\alpha \] \[[{{H}^{+}}]=0.1\times \frac{1}{100}={{10}^{-3}}\] pH\[=-\log \,\,[{{H}^{+}}]=-\log \,{{10}^{-3}}=3\]You need to login to perform this action.
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