A) Increasing
B) Decreasing
C) Neither increasing nor decreasing
D) None of these
Correct Answer: C
Solution :
Let\[f(x)={{x}^{2}}-x+1\], \[f'(x)=2x-1\] Obviously \[f'(0)=-1\] and \[f'(1)=1\] Thus function is neither increasing nor decreasing.You need to login to perform this action.
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