A) Increasing
B) Decreasing
C) Neither increasing nor decreasing
D) None of these
Correct Answer: B
Solution :
\[f(x)=x\sin x+\cos x+{{\cos }^{2}}x\] \[\therefore f'(x)=\sin x+x\cos x-\sin x-2\cos x\sin x\] \[=\cos x(x-2\sin x)\] Hence \[x\to 0\] to \[\pi \], then \[f'(x)<0\] i.e., \[f(x)\]is decreasing function.You need to login to perform this action.
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