A) \[(-\infty ,\infty )\]
B) \[(-2,\,0)\]
C) \[(2,\infty )\]
D) \[(0,\,2)\]
Correct Answer: D
Solution :
\[\frac{dy}{dx}=\frac{-1}{{{e}^{x}}}x(x-2)\] is \[+ve\]when \[x(x-2)\]is \[-ve\] i.e., x lies in the interval (0, 2), exponential function as we know is always \[+ve\].You need to login to perform this action.
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