A) \[x>1\]
B) \[x>2\]
C) \[x<1\]
D) \[x<2\]
Correct Answer: C
Solution :
\[f(x)={{(x-1)}^{2}}-1\]. Hence decreasing in x < 1. Aliter : \[f'(x)=2x-2=2(x-1)\] To be decreasing, \[2(x-1)<0\Rightarrow (x-1)<0\Rightarrow x<1\].You need to login to perform this action.
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