A) \[1<x<2\]
B) \[x>2\]
C) \[x<1\]
D) None of these
Correct Answer: A
Solution :
Here \[f(x)=y=2{{x}^{3}}-9{{x}^{2}}+12x-6\] \[\Rightarrow \]\[f'(x)=6{{x}^{2}}-18x+12\] Since\[f(x)\]is increasing or decreasing in \[(a,b)\] according as \[f'(x)>0\]or \[<0\]for every \[x\in (a,b)\]. Hence \[f'(x)=6(x-2)(x-1)\] which is obviously decreasing if \[x\in (1,2)\,\,\,i.e.,\,1<x<2\].You need to login to perform this action.
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