A) \[\frac{5}{4}\]
B) \[\frac{3}{4}\]
C) \[\frac{4}{3}\]
D) \[\frac{4}{5}\]
Correct Answer: A
Solution :
In\[\frac{c}{d}=\frac{L.C.M.(a,c)}{H.C.F.(b,d)}\],by Pythagoras' theorem, \[\Rightarrow \] \[L.C.M.\]\[\frac{6}{14}and\frac{2}{7}\]You need to login to perform this action.
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