A) \[\text{6}0{}^\circ \]
B) \[\text{45}{}^\circ \]
C) \[\text{3}0{}^\circ \]
D) \[\text{9}0{}^\circ \]
Correct Answer: B
Solution :
\[\Rightarrow \] From the tables, \[\frac{L.C.M.(6,2)}{H.C.F.(14,7)}=\frac{6}{7}\]. Therefore \[\text{7}\times \text{13}+\text{13}=\text{1}0\text{4}=\text{23}\times \text{13}\]\[\therefore \]\[\text{7}\times \text{13}+\text{13}\]You need to login to perform this action.
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