A) \[0.3\]
B) \[{{\tan }^{-1}}(1.3)\]
C) \[{{\tan }^{-1}}(0.3)\]
D) \[{{\tan }^{-1}}\left( \frac{1}{18} \right)\]
Correct Answer: C
Solution :
\[x+y={{\tan }^{-1}}33\,\,\,\Rightarrow y={{\tan }^{-1}}33-{{\tan }^{-1}}3\] \[={{\tan }^{-1}}\frac{33-3}{1+99}={{\tan }^{-1}}\frac{30}{100}\]Þ \[y={{\tan }^{-1}}(0.3)\].You need to login to perform this action.
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