A) \[\frac{3}{4},\frac{-3}{8}\]
B) \[\frac{3}{4},\frac{3}{8}\]
C) \[\frac{4}{3},\frac{3}{8}\]
D) None of these
Correct Answer: D
Solution :
\[\frac{x-1}{x+1}+\frac{2x-1}{2x+1}=\frac{23}{36}\left[ 1-\frac{(x-1)(2x-1)}{(x+1)(2x+1)} \right]\] Þ \[24{{x}^{2}}-23x-12=0\Rightarrow (3x-4)(8x+3)=0\]. Hence the result.You need to login to perform this action.
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